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11x^2-41x-100=0
a = 11; b = -41; c = -100;
Δ = b2-4ac
Δ = -412-4·11·(-100)
Δ = 6081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{6081}}{2*11}=\frac{41-\sqrt{6081}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{6081}}{2*11}=\frac{41+\sqrt{6081}}{22} $
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